- The molecule contains both oxygen and bromine, and from the analysis, contains five double bonds or rings. The large number of degrees of unsaturation strongly suggests an aromatic compound (DU = 4).
- The mass spectrum displays a molecular ion, an m-1 peak and a peak corresponding to loss of a CHO unit. The strong m-1 peak is also suggestive of an aldehyde.
- The 13C spectrum contains seven peaks, indicating that the molecule has no symmetry. The peaks in the aromatic region strongly suggest 1,3-disubstitution, and there is a singlet at d 190 which would be consistent with a aldehyde carbon.
- The proton NMR also shows evidence for an aldehyde CH and the complex splitting pattern in the aromatic region is consistent with 1,2 or 1,3-disubstitution on an aromatic ring.
- The IR shows sharp peaks for unsaturated (sp2) CH, a characteristic aldehyde CH stretch at around 2800 cm-1 and peaks consistent with double bond stretching.
- The simplest structure which is consistent with all of these data would be a 1,2 or 1,3-disubstitution aromatic compound bearing bromine and aldehyde residues.
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