Problem #6: The molecular formula for an unknown compound is C14H18O4. Data for the 1H NMR, 13C NMR, infrared and mass spectra for this compound are available by clicking on the buttons below; use the "Return" button to return to this screen. Help with the interpretation of each spectrum is available and you can review background and selected correlation tables by clicking on the links in the MENU above. Using the spectral and analytical information provided, determine the structure for this compound.



















 

NMR Spectrum
Problem #6: C14H18O4



















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Problem #6: C14H18O4



















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Problem #6: C14H18O4




















13C NMR: quartet: 13.6 ppm triplet: 35.7 ppm doublet: 57.8 ppm triplet: 59.5 ppm s: 141.1; d: 125.3, 127.6, 128.7 ppm singlet: 174.5 ppm

Problem #6: C14H18O4



















  • The molecule contains four oxygens, and from the analysis, contains six double bonds, carbonyls or rings. The large number of degrees of unsaturation strongly suggests an aromatic compound (DU = 4).
  • The mass spectrum displays a molecular ion, an m-45 and a peak at m/e = 91, all of which are consistent with a molecule containing benzyl and ethoxy groups.
  • The 13C spectrum contains six peaks, indicating that the molecule has some elements of symmetry. The quartet at d 56 and the triplet at d 71 represent a CH3 and a CH2 group which are deshielded by electronegative atoms (most likely oxygen); the peaks at d 161 - 128 are in the aromatic region; the fact that three doublets and one singlet are observed strongly suggests monosubstitution.
  • The proton NMR also shows evidence for two ethyl groups, a CH-CH2- group, and a monosubstituted aromatic group; the chemical shift suggests that the carbons of the CH-CH2- adjacent to one or more electronegative groups.
  • The IR is consistent with an aromatic compound containing a carbonyl group.
  • The simplest structure which is consistent with all of these data would be an aromatic compound linked via a -CH2CH group to a diethyl ester.